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Lpi LPIC-1 Exam 102, Part 2 of 2, version 5.0 Sample Questions (Q206-Q211):
NEW QUESTION # 206
Which of the following tasks can the date command accomplish? (Choose two.)
- A. Set the system's date but not the time.
- B. Calculate the time span between two dates.
- C. Display time in a specific format.
- D. Print a calendar for a month or a year.
- E. Set the system's date and time.
Answer: C,E
Explanation:
The date command is used to display or set the system's date and time. The date command has the following syntax:
date [options] [+format] [time]
The options can modify the behavior of the date command, such as setting the time zone, printing the date in RFC 3339 format, or updating the hardware clock. The +format argument can specify the output format of the date command, using various conversion specifiers that represent different components of the date and time, such as %Y for the year, %m for the month, %d for the day, %H for the hour, %M for the minute, and %S for the second. The time argument can set the system's date and time, using the format MMDDhhmm[[CC]YY][.ss], where MM is the month, DD is the day, hh is the hour, mm is the minute, CC is the century, YY is the year, and ss is the second.
Therefore, the date command can accomplish the following tasks:
A . Set the system's date and time. For example, to set the system's date and time to November 8, 2023, 18:30:00, the command would be:
date 110818302023.00
E . Display time in a specific format. For example, to display the current date and time in the format YYYY-MM-DD HH:MM:SS, the command would be:
date +%Y-%m-%d %H:%M:%S
The other options in the question are not correct for this task. The date command cannot set the system's date but not the time, as the time argument requires both the date and the time components. The date command cannot calculate the time span between two dates, as it can only display or set the current date and time. The date command cannot print a calendar for a month or a year, as that is the function of the cal command.
Reference:
LPI 102-500 Exam Objectives, Topic 105.1: Customize and use the shell environment LPI 102-500 Study Guide, Chapter 5: Customizing Shell Environments, Section 5.1: Working with the Shell date man page
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NEW QUESTION # 207
What word is missing from the following SQL statement?
__________ count(*) from tablename;
(Please specify the missing word using lower-case letters only.)
Answer:
Explanation:
select
Explanation:
The missing word is select, which is the keyword used to query data from a table in SQL. The select statement has the following syntax:
select column_list from table_name where condition;
The column_list can be one or more columns separated by commas, or an asterisk () to indicate all columns. The table_name is the name of the table that contains the data. The where clause is optional and specifies a condition to filter the rows. The count() function is an aggregate function that returns the number of rows in the table or in a group. Therefore, the complete statement is:
select count(*) from tablename;
This statement will return the number of rows in the table named tablename. Reference: SQL COUNT() Function - W3Schools, SQL COUNT: The Ultimate Guide To SQL COUNT Function - SQL Tutorial, The SQL Count Function Explained With 7 Examples.
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NEW QUESTION # 208
Which of the following SQL queries counts the number of occurrences for each value of the field order_type in the table orders?
- A. SELECT AUTO_COUNT FROM orders COUNT order_type;
- B. COUNT(SELECT order_type FROM orders);
- C. SELECT order_type,COUNT(*) FROM orders WHERE order_type=order_type;
- D. SELECT COUNT(*) FROM orders ORDER BY order_type;
- E. SELECT order_type,COUNT(*) FROM orders GROUP BY order_type;
Answer: E
Explanation:
The correct SQL query to count the number of occurrences for each value of the field order_type in the table orders is:
SELECT order_type,COUNT(*) FROM orders GROUP BY order_type;
This query uses the SELECT statement to retrieve the values of the order_type field and the COUNT(*) function to count the number of rows for each order_type. The GROUP BY clause groups the rows by the order_type field, so that the count is calculated for each distinct value of order_type. The result of this query is a table with two columns: order_type and count, where each row shows the number of orders for a specific order_type.
The other options are incorrect for the following reasons:
A: This query uses a WHERE clause that is always true, since order_type=order_type for every row. Therefore, this query returns the same result as SELECT order_type,COUNT(*) FROM orders;, which is a table with one row that shows the total number of orders, regardless of the order_type.
C: This query is syntactically invalid, since the COUNT function cannot take a subquery as an argument. The correct way to use a subquery with COUNT is COUNT((SELECT order_type FROM orders));, which returns the total number of orders, regardless of the order_type.
D: This query uses the ORDER BY clause to sort the rows by the order_type field, but it does not group them by order_type. Therefore, this query returns the same result as SELECT COUNT(*) FROM orders;, which is a table with one row that shows the total number of orders, regardless of the order_type.
E: This query is syntactically invalid, since there is no such function as AUTO_COUNT in SQL, and the COUNT function cannot take a field name as an argument. The correct way to use COUNT with a field name is COUNT(order_type);, which returns the number of non-null values in the order_type field.
Reference:
[SQL COUNT Function]
[SQL GROUP BY Statement]
[SQL SELECT Statement]
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NEW QUESTION # 209
What command should be used to print a listing of email in the system's mail queue?
- A. lpq
- B. mlq
- C. sendmail -l
- D. mailq
Answer: D
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NEW QUESTION # 210
Which of the following is a valid IPv6 address?
- A. 2001:db8:3241::1
- B. 2001.db8.819f..1
- C. 2001:db8:0g41::1
- D. 2001%db8%9990%%1
- E. 2001::db8:4581::1
Answer: A
Explanation:
A valid IPv6 address is represented as a set of 16-bit hexadecimals separated by colons. The address is divided into eight groups, and each 16-bit group is represented by four hexadecimal numbers. A valid IPv6 address is in the form "x1:x2:x3:x4:x5:x6:x7:x8" where each xi is a hexadecimal string which may contain digits, lower-case English letter ('a' to 'f') and upper-case English letters ('A' to 'F'). Leading zeros are allowed in xi. The longest sequence of consecutive all-zero fields is replaced with two colons (::).1 Option A is the only one that follows these rules. Option B has two consecutive colons twice, which is not allowed. Option C has an invalid hexadecimal character 'g'. Option D uses percentage signs instead of colons, which is not a valid separator. Option E uses dots instead of colons, and has two consecutive dots, which are both invalid.
References: 1: IPv4 and IPv6 address formats - IBM
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NEW QUESTION # 211
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